java program to check armstrong

An Armstrong number of three digits is an integer such that the sum of the cubes of its digits is equal to the number itself. For example, 371 is an Armstrong number since 3**3 + 7**3 + 1**3 = 371.

                       Algorithm

 INTEGER :: a, b, c                   ! the three digits
   INTEGER :: abc, a3b3c3               ! the number and its cubic sum
   INTEGER :: Count                     ! a counter

   Count = 0
   DO a = 0, 9                          ! for the left most digit
      DO b = 0, 9                       !   for the middle digit
         DO c = 0, 9                    !     for the right most digit
            abc    = a*100 + b*10 + c   !        the number
            a3b3c3 = a**3 + b**3 + c**3 !        the sum of cubes
            IF (abc == a3b3c3) THEN     !        if they are equal
               Count = Count + 1        !           count and display it
               WRITE(*,*)  'Armstrong number ', Count, ': ', abc
            END IF
         END DO
      END DO
   END DO

END PROGRAM

                                     Program 

import java.util.Scanner;

public class Armstrong

{

public static void main(String args[])

{

int n, nu, num=0,rem;

Scanner scan = new Scanner(System.in);

System.out.print("Enter any Positive Number : ");

n = scan.nextInt();

nu = n;

while(nu!= 0)

{

rem = nu%10;

num = num + rem*rem*rem;

nu = nu/10;

}

if(num == n)

{

System.out.println("Armstrong Number");

}

else{

System.out.println("Not an Armstrong Number");

}

}

}